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【已解决】Scrapy如何加载全部网页内容

Scrapy crifan 415浏览 0评论

折腾:

【记录】用Python的Scrapy去爬取Youtube中Humf的字幕

期间,

已经可以去用scrapy打开页面:

http://www.yousubtitles.com/load/?url=https%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3D23t1f8d2ISs%26index%3D1%26list%3DPLHOR8x-IicVJDAmJWZmJ-IMu1x3lTAld5

了,但是返回的页面,却是没有加载全部的内容:

全部加载的应该是这样的:

scrapy page load not completed

python – Scrapy response incomplete – Stack Overflow

scrapy page loading

python – Wait until the webpage loads in Scrapy – Stack Overflow

python – Parsing a slow-loading webpage with scrapy in combination with selenium – Code Review Stack Exchange

还是去用chrome调试,看看到底加载了数据的js和请求是什么

找到了:

POST /loadvideo/23t1f8d2ISs HTTP/1.1

Host: www.yousubtitles.com

Connection: keep-alive

Content-Length: 0

Pragma: no-cache

Cache-Control: no-cache

Accept: application/json, text/javascript, */*; q=0.01

Origin: http://www.yousubtitles.com

X-Requested-With: XMLHttpRequest

User-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_3) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/64.0.3282.186 Safari/537.36

Referer: http://www.yousubtitles.com/load/?url=https%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3D23t1f8d2ISs%26index%3D1%26list%3DPLHOR8x-IicVJDAmJWZmJ-IMu1x3lTAld5

Accept-Encoding: gzip, deflate

Accept-Language: zh-CN,zh;q=0.9,en;q=0.8

Cookie: _ym_uid=1519808696639134764; _ym_isad=2; _ym_visorc_40164390=w; __atuvc=13%7C9; __atuvs=5a98a5092e989c01003

HTTP/1.1 200 OK

Server: nginx

Date: Fri, 02 Mar 2018 01:55:54 GMT

Content-Type: text/html; charset=utf-8

Content-Length: 1907

Connection: keep-alive

Vary: Accept-Encoding

Content-Encoding: gzip

而得到的其中links是html的encode后的内容:

需要反向解析后,才能方便获取其中的href的链接地址

所以现在清楚了:

实际上此处用Scrapy去抓取的页面,只是普通的静态网页,而其中想要的内容是通过js动态的额外的http的post请求获得的。

所以此处想要实现:Scrapy加载全部网页内容,需要自己去调试页面,找到对应的js的http的请求,然后代码中再去模拟即可。

此处找到的额外的js的http请求是:

Request URL:http://www.yousubtitles.com/loadvideo/23t1f8d2ISs

Request Method: POST

然后再去解析返回的内容。

代码:

<code>import re

            foundVideoId = re.search(r'v=(?P&lt;videoId&gt;[\w\-]+)', singleVideoUrl)
            if foundVideoId:
                videoId = foundVideoId.group("videoId")
                self.logger.info("videoId=%s", videoId) # u'23t1f8d2ISs'

                # http://www.yousubtitles.com/loadvideo/23t1f8d2ISs
                loadVideoUrl = "http://www.yousubtitles.com/loadvideo/" + videoId
                self.logger.info("loadVideoUrl=%s", loadVideoUrl) # u'http://www.yousubtitles.com/loadvideo/23t1f8d2ISs'
                yield scrapy.Request(url=loadVideoUrl, callback=self.parseLoadVideoResp, method="POST")

def parseLoadVideoResp(self, response):
    """
    parse response of yousubtitles load video for each youtube video id
    :param response:
    :return:
    """
    # for debug
    self.saveHtml("loadvideo", response.body)
    respUrl = response.url
    self.logger.info("respUrl=%s", respUrl)
</code>

效果是:

可以获得返回的内容:

然后接着就可以去进行后续的解析等内容了。

【总结】

此处用Scrapy去抓取的页面,只是普通的静态网页,而其中想要的内容是通过js动态的额外的http的post请求获得的。

所以此处想要实现:Scrapy加载全部网页内容,需要自己去调试页面,找到对应的js的http的请求,然后代码中再去模拟即可。

而具体的额外的http请求是什么,需要自己调试页面去找的。

调试工具推荐Chrome/Firefox/Safari等,都可以。

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